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March 4, 2015

March 4, 2015

Posted by **jerson** on Sunday, November 15, 2009 at 7:27am.

x/3=x/5-2

- pre algebra -
**Average Man**, Sunday, November 15, 2009 at 11:24amSince 5-2=3, saying x/3=x/3 isn't really saying anything. Multiply each side by 3/1 if you don't believe me. Did you copy it down correctly?

- pre algebra -
**Brit**, Sunday, November 15, 2009 at 7:36pmok so for this you do

x/3=x/5-2

you multiple both sides by 3

so you have

x=x/15 -6

then go on from there

- pre algebra -
**PsyDAG**, Tuesday, November 17, 2009 at 1:37amBrit's math is incorrect.

In contrast to Averageman, I am assuming that your equation is really:

x/3 = x/5 - 2

Not x/3 = x/(5-2)

Multiply both sides by 15 to get rid of*both*denominators.

5x = 3x - 30

Subtract 3x from both sides.

2x = -30

Divide both sides by 2.

x = -15

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