Posted by **Nikki** on Saturday, November 14, 2009 at 4:07pm.

Determine an equation of the circle that is tangent to both axes, has its center in the fourth quadrant and passes through the point (8, -9).

Help please?

Thanks much!

- Math -
**bobpursley**, Saturday, November 14, 2009 at 4:22pm
well, you know if it is tangent to both axis, the center is at r,-r

It passes through 8,-9 so the distance from that point to the center is also r.

r^2=(8-r)^2 + (-9+r)^2

= 64-16r+r^2+81-18r+r^2

r^2-34r-145=0

(r-29)(r-5)=0

r=29, or r=5

check both answers.

then put it in standard form.

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