How many calories of heat are required to raise the temperature of 550g of water from 12.0 degrees celcius to 18.0 degrees celcuis
q = mc*delta T.
q = 550 g x 1 cal/g*C x (18-12) = ??
Note the correct spelling of celsius.
13,807.2
To calculate the amount of calories of heat required to raise the temperature of water, we can use the formula:
Q = m * C * ΔT
Where:
Q = amount of heat energy (in calories)
m = mass of water (in grams)
C = specific heat capacity of water (1 calorie/gram °C)
ΔT = change in temperature (in °C)
First, we need to determine the change in temperature:
ΔT = final temperature - initial temperature
= 18.0°C - 12.0°C
= 6.0°C
Next, we can substitute the values into the formula:
Q = 550g * 1cal/g°C * 6.0°C
Calculating this, we get:
Q = 3,300 calories
Therefore, 3,300 calories of heat are required to raise the temperature of 550g of water from 12.0°C to 18.0°C.