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July 30, 2014

July 30, 2014

Posted by **Pre Calc** on Friday, November 13, 2009 at 2:40pm.

sec ( - pi/18) * cos (37 pi)/18

I do not see how to do this problem. Every time I do it out I get a reference angle of twenty degrees which isn't on the unit circle. I do it on my calculator and get answer of one. If you could show me how to do this problem that would be great. I think the part I'm getting stuck on is the - pi/8 there must be some other rule that I do not know about when there are negetives

- Pre Calc -
**bobpursley**, Friday, November 13, 2009 at 2:55pmsec(-pi/18)*cos(37PI/18)

Remember that cos(-theta)=cos(theta)

so sec(theta)=sec(-theta)

sec(pi/18)cos(37Pi/18)

sec(2PI +Pi/18)cos(37PI/18)

sec(37pi/18)cos(37PI/18)

1/cos * cos= 1

- Pre Calc -
**Pre Calc**, Friday, November 13, 2009 at 3:02pmhow did you go from the first line to the next in these lines

sec(2PI +Pi/18)cos(37PI/18)

sec(37pi/18)cos(37PI/18)

1/cos * cos= 1

- Pre Calc -
**bobpursley**, Friday, November 13, 2009 at 4:22pmany trig function is periodic by 2PI.

sin (theta)=sin(theta+2PI)

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