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Physics

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A 325-kg boat is sailing 15.0° north of east at a speed of 2.00 m/s. Thirty seconds later, it is sailing 35.0° north of east at a speed of 4.00 m/s. During this time, three forces act on the boat: a 31.0-N force directed 15.0° north of east (due to an auxiliary engine), a 23.0-N force directed 15.0° south of west (resistance due to the water), and (due to the wind). Find the magnitude and direction of the force . Express the direction as an angle with respect to due east.

  • Physics - ,

    Fnet=Fb+Fr+Fw
    Fnet=ma
    a=change v/change t = 2/30=0.0667
    fnet=325(0.0667)=21.67N

    21.67=31+(-23)+Fw
    Fw=13.7N 15 North of East

    35.0 is an irrelivant detail - fw can be calculated with the given times and masses

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