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March 28, 2017

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A 75 kg box slides down a 25.0 degree ramp with an acceleration of 3.60 m/s^2.

Find coefficient between the box and the ramp.

What acceleration would a 175 kg box have on this ramp?

  • Physics - ,

    The net force down the ramp is
    (mass) x (acceleration) = 75*3.60 = 270 N

    The component of weight down the ramp is
    M g sin 25 = 310.6 M

    The friction force is the difference between those two numbers, 40.6 N

    The kinetic friction coefficient is
    (friction force)/(normal weight component)
    = 40.6/[735 cos 25] = 0.06

  • Physics - ,

    1.54

  • Physics - ,

    a)F=ma Fg=mg 310.9-270 cos(25)735
    75(3.60) 75(9.81) 41N 667N
    735
    F parallel= sin(25)735=310.9N

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