The deepest point in the ocean is 11km below sea level, deeper than Mt. Everest is tall.What is the pressure in atmospheres at this depth?

pressure= atm pressure+ pressure pgh

pressure due to height= pgh= 1000kg/m3 *9.8m/s* 11000m = 107800kPa
1atm=101.3Kpa so 107800kPa=1064.16 atm

total pressure= 1+1064.16atm
=1065 atm.
=rounding to two sig fig: 1100atm

To calculate the pressure at a certain depth in the ocean, you can use the hydrostatic pressure equation. The equation states that the pressure at a given depth is equal to the weight of the fluid column above it.

In this case, we'll consider the pressure at the deepest point in the ocean, which is approximately 11 kilometers below sea level. Firstly, we need to convert the depth from kilometers to meters since the SI unit for pressure is Pascal (Pa), which is based on meters.

1 kilometer (km) = 1,000 meters (m)

Therefore, 11 kilometers = 11,000 meters.

Next, we need to know the density of seawater, which is approximately 1,025 kilograms per cubic meter (kg/m³).

Using these values, we can calculate the pressure at the deepest point in the ocean using the equation:

Pressure = Density * Gravity * Depth

Where:
Density = 1,025 kg/m³ (density of seawater)
Gravity = 9.8 m/s² (acceleration due to gravity on Earth)
Depth = 11,000 m (depth below sea level)

Plugging in these values, the equation becomes:

Pressure = 1,025 kg/m³ * 9.8 m/s² * 11,000 m

Calculating this, we find that the pressure at the deepest point in the ocean is approximately 1,126,850,000 Pascal (Pa), which is equivalent to 1,113 atmospheres (atm) rounded to three significant figures.

So, the pressure at the deepest point in the ocean is approximately 1,113 atmospheres.