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Algebra

posted by on .

Did I do this right?

Find the vertex, the x intercepts and y intercepts.

f(x)=(x-2)^2-4

Vertex: 2,4

X intercepts: 0,0 4,0

Y intercepts: I didn't know how to get these. Could you explain?

  • Algebra - ,

    Isn't the vertex at 0,-4?

    y intercepts are when x is zero
    y=-2^2-4 or 0

    x intercepts are when y is zero
    0=(x-2)^2 -4
    x-2=+-2
    x=0, 4

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