Posted by Frank on Thursday, November 12, 2009 at 6:05pm.
Hi I'm kinda new here, and hope someone can please help me out.
A person exerts a tangential force of 38.1 N on the rim of a diskshaped merrygoround of radius 2.74 m and mass 207 kg.
If the merrygoround starts at rest, what is its angular speed after the person has rotated it through an angle of 32.5degrees?
Any help would be appreciated!

Physics  bobpursley, Thursday, November 12, 2009 at 6:15pm
Torque= I alpha
38.1*2.74=I alpha
For I,use a solid disk.
solve for angular acceleation, alpha
wf^2 = 2*alpha*displacement, where displacement is 32.5deg in RADIANS