Homework Help: Physics

Posted by Frank on Thursday, November 12, 2009 at 6:05pm.

Hi I'm kinda new here, and hope someone can please help me out.

A person exerts a tangential force of 38.1 N on the rim of a disk-shaped merry-go-round of radius 2.74 m and mass 207 kg.
If the merry-go-round starts at rest, what is its angular speed after the person has rotated it through an angle of 32.5degrees?

Any help would be appreciated!

Physics - bobpursley, Thursday, November 12, 2009 at 6:15pm
Torque= I alpha

38.1*2.74=I alpha
For I,use a solid disk.

solve for angular acceleation, alpha

wf^2 = 2*alpha*displacement, where displacement is 32.5deg in RADIANS

Answer this Question

Related Questions

physics - An 77 person stands on a uniform ladder 4.0 long, that weighs 100 , as...
physics - A person exerts a horizontal force of F = 174 N in the test apparatus ...
Physics - A person exerts a horizontal force of F = 179 N in the test apparatus ...
Physics - A 75 kg person escapes from a burning building by jumping from a ...
physics - Initially a small car and a truck are at rest then the car starts ...
physics - A boy exerts a horizontal force of 2nt to pull his 2kg sled over the ...
Physics - b) If the car is moving much faster than the heavier truck when they ...
phsyics HELP PLEASE - A 40.6-kg crate rests on a horizontal floor, and a 69.1-kg...
Physics - Hello everyone I know that when a force is applied it has to exert a ...
physics - A 33.6-kg crate rests on a horizontal floor, and a 64.7-kg person is ...

For Further Reading

First Name:
School Subject:
Answer: