Posted by **Anonymous** on Thursday, November 12, 2009 at 3:37pm.

A softball of mass 0.200 kg that is moving with a speed of 8.2 m/s collides head-on and elastically with another ball initially at rest. Afterward the incoming softball bounces backward with a speed of 3.9 m/s.

1. Calculate the velocity of the target ball after the collision.

2. Calculate the mass of the target ball.

- Physics -
**bobpursley**, Thursday, November 12, 2009 at 3:46pm
Conservation of momentum leads to

.2kg*8.2m/s=.2kg*(-3.9)m/s + Mass*V

Solve for V in therms of all the other.

Then put that into this for V

conservation of energy.

1/2 .2 *8.2^2=1/2 .2*(3.9)^2 + 1/2 MV^2

then solve for mass, after that, go back and solve for V

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