Posted by michael on Thursday, November 12, 2009 at 1:31am.
1) For the average value of the SLOPE of f(x) in that interval, calculate Integral of f'(x) from 4 to 5. You have to divide by the interval to get the average, but that is 1.
f'(x) = 2/sqrtx
Average value = INTEGRAL 2 x^-1/2 dx
from 4 to 5
= 4 (sqrt 5 - sqrt 4) = 0.9443
2) Now that you have the average value of f'(x), find the value of c such that f'(c) = f'(x)(average)
2/sqrtc = 0.9443
sqrt c = 2.118
c = 4.486
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