Physics 30
posted by ALan .
An object located in front of a concave mirror with a radius of curvature of 80 cm produces an invert image that is three times the size of the object. Calculate the distance between the object and the mirror.

I got stuck after i attempted to use 1/f=1/di+1/do, seeing as how i need di, which i don't have.

The inverted image is real, and di/do = 3 because of the stated magnification.
The focal length is f = R/2 = 40 cm
1/do + 1/(3do) = 1/40
4/(3 do) = 1/40
160 = 3 do
Solve for do 
Thanks

WHAT IS RESONANCE

WHAT IS RESONANCE

DEFIN RETARDATION