calculate the density of O2 gas( in g/L) at 1.22 atm and 25 degrees C
1.595 or 1.60
Use PV = nRT.
Calculate n, number of moles.
n x molar mass = grams.
If you plugged in 1.00 L for the volume, then g/L will be the density.
Why did the oxygen molecule go to school? To get smarter, of course! Now, let's calculate the density.
To find the density of a gas, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.
First, let's convert the pressure to atm and the temperature to Kelvin:
Pressure (P) = 1.22 atm
Temperature (T) = 25 degrees C + 273.15 = 298.15 K
Next, we need to identify the molar mass of oxygen, which is 32 g/mol.
Since we're solving for density in grams per liter (g/L), we can rearrange the ideal gas law equation to solve for density (d):
d = (P * Molar mass) / (R * T)
Substituting the values into the equation:
d = (1.22 atm * 32 g/mol) / (0.0821 L·atm/mol·K * 298.15 K)
After calculating, the density of O2 gas at 1.22 atm and 25 degrees C is approximately 1.43 g/L.
Hope that answers your question and puts a smile on your face!
To calculate the density of a gas, you need to use the ideal gas law equation, which states:
PV = nRT
Where:
P = pressure of the gas (in atm)
V = volume of the gas (in L)
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature of the gas (in Kelvin)
First, let's convert the given temperature from degrees Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 25°C + 273.15
T(K) = 298.15 K
Now, we can rearrange the ideal gas law equation to solve for density:
Density = (n * M) / V
Where:
Density = density of the gas (in g/L)
n = number of moles of the gas
M = molar mass of the gas (in g/mol)
V = volume of the gas (in L)
The molar mass of O2 gas is 32.00 g/mol.
We can calculate the number of moles using the ideal gas law equation:
n = (PV) / (RT)
n = (1.22 atm) / (0.0821 L·atm/(mol·K)) * (298.15 K)
n = 0.0498 mol
Finally, we can substitute the values into the density equation:
Density = (n * M) / V
Density = (0.0498 mol * 32.00 g/mol) / V
Density = 1.5936 g/L
Therefore, the density of O2 gas at 1.22 atm and 25 degrees Celsius is approximately 1.59 g/L.