The highest that George can suck water up a very long straw is 2.0 m. (This is a typical value.)
What is the lowest pressure that he can maintain in his mouth?
Sorry, I meant you are the BEST
The weight of the water must equal the difference in pressure.
atmospheric pressure-his pressure=weight 2M water.
101.3kPa*area-hispressure*area=area*2m*densitywater*g
101.3kpa-hispressure=
2m*10^3kg/m^3*9.8N/kg
his pressure=101.3kpa-18.6kPa
check my figuring.
you's the best
There is an error. 2*9.8=19.6, not 18.6
change that.
oh i figured that...thanks again
82kPa
To determine the lowest pressure that George can maintain in his mouth, we can use the principles of fluid pressure. When George sucks water up a straw, he creates a pressure difference between the top and bottom of the straw.
The pressure at any point in a fluid (in this case, the water in the straw) depends on two factors: the density of the fluid (ρ) and the height of the fluid column (h). The relationship between pressure (P), density (ρ), and height (h) is given by the equation:
P = ρgh,
where g represents the acceleration due to gravity (approximately 9.8 m/s²).
Since George can suck water up the straw to a height of 2.0 m, we can substitute these values into the equation:
P = ρgh = (density of water) * (acceleration due to gravity) * (height)
= (1000 kg/m³) * (9.8 m/s²) * (2.0 m)
= 19600 Pascal (Pa).
Therefore, the lowest pressure that George can maintain in his mouth is approximately 19600 Pa.