Posted by SB on Wednesday, November 11, 2009 at 8:17pm.
The weight of the water must equal the difference in pressure.
atmospheric pressure-his pressure=weight 2M water.
101.3kPa*area-hispressure*area=area*2m*densitywater*g
101.3kpa-hispressure=
2m*10^3kg/m^3*9.8N/kg
his pressure=101.3kpa-18.6kPa
check my figuring.
you's the best
Sorry, I meant you are the BEST
There is an error. 2*9.8=19.6, not 18.6
change that.
oh i figured that...thanks again
82kPa
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