Posted by beto on .
the equation is x^2 + y^2 =sqrt(7)
i knw 2x+2y dy/dx= don't knw if sqrt(7)= 0 for this problem or 1/2(7)^1/2
so wat do i do for sqrt(7) in this problem?

Calculus, implicit differentation 
bobpursley,
Denke! sqrt7 is a constant. The differential of a constant is zero.
2x+2y dy/dx=0
solve for dy/dx 
Calculus, implicit differentation 
beto,
ok thank you...
so it would be dy/dx=2x/2y
giving me dy/dx=x/y