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March 28, 2017

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the equation is x^2 + y^2 =sqrt(7)
i knw 2x+2y dy/dx= don't knw if sqrt(7)= 0 for this problem or 1/2(7)^-1/2
so wat do i do for sqrt(7) in this problem?

  • Calculus, implicit differentation - ,

    Denke! sqrt7 is a constant. The differential of a constant is zero.

    2x+2y dy/dx=0
    solve for dy/dx

  • Calculus, implicit differentation - ,

    ok thank you...
    so it would be dy/dx=-2x/2y
    giving me dy/dx=-x/y

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