Posted by **Anonymous** on Wednesday, November 11, 2009 at 2:17pm.

A tennis ball of mass m = 0.065 kg and speed v = 25 m/s strikes a wall at a 45° angle and rebounds with the same speed at 45° (Fig. 7-29). What is the impulse given the wall?

I started out with finding the momentum and doubling it to get the impulse on the wall but that isn't the right answer. What equation do I need to start this one? Does it have to do with the angles they are giving me?

- Physics -
**bobpursley**, Wednesday, November 11, 2009 at 2:20pm
No, that is not right. Only the normal component doubles.

Vfinalnormal =25*.707*2

Force*time=m*vfinalnormal

You have to only dealt with what changed, the momentum normal, and the implulse norma.

## Answer this Question

## Related Questions

- physics for scientists and engeneers I - A tennis ball of mass m = 0.065 kg and ...
- PHYSICS PLEASE HELP!! - A tennis ball of mass= 0.058 kg and speed= 19 m/s ...
- physics-impulse - A tennis ball of mass m = 0.068kg and speed v = 21m/s strikes ...
- Physics - A tennis ball of mass= 0.058 kg and speed= 19 m/s strikes a wall at a ...
- Physics - You are hitting a tennis ball against a wall. The 0.057-kg tennis ball...
- Physics - A 275-gram ball bounces off a wall. The ball stays in a horizontal ...
- physics - A mass of 100g strikes the wall with speed 5m/s at an angle of 60 and ...
- physics - A ball of mass m strikes a wall that is perpendicular to its path at ...
- physics - A 1 kg steel ball strikes a wall with a speed of 9.99 m/s at an angle ...
- physics - A 1 kg steel ball strikes a wall with a speed of 9.99 m/s at an angle ...

More Related Questions