Homework Help: Chemistry

Posted by Anonymous on Wednesday, November 11, 2009 at 7:34am.

ive calculated the amount of change for an enzyme controlled reaction as 1.5625 x 10^-8 mol.min-1 and ive been asked to find the activity of the enzyme in micromoles product formed per min per mg of enzyme how do i do this

i have 10 micro litres of a 5mg ml -1 of the enzyme ???

Any help/explanation would be appreciated !!

Chemistry - bobpursley, Wednesday, November 11, 2009 at 8:36am
10E-6liters*5E-3g/1E-3l= 50micrograms

product/(min*mg)= 1.5625E-8mol/(min*.050mg)
= 3.125E-7 mol/min*mg

Now you want that in micro moles..
= .3125micromole/min*mg

check my calcs.

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