Tuesday

March 3, 2015

March 3, 2015

Posted by **Salman** on Wednesday, November 11, 2009 at 4:31am.

Let (x_1 = -1\) be the initial approximation.

The second approximation (x_2) is ?

and the third approximation (x_3) is ?

- Calculus -
**Reiny**, Wednesday, November 11, 2009 at 8:14amFirst of all, why not reduce it to

x^3 + 2x + 2 = 0

Your iteration formula should be

x_{new = (2x^3 - 2)/(3x^2 + 2) so for a start of x=-1 we get x1 = -1.333333 x2 = -.91919 x3 = -.78357 BTW, x5 = -.770917 which is correct to 7 decimal places. } - Calculus -
**Reiny**, Wednesday, November 11, 2009 at 1:21pmlooks like I forgot to close my subscript code

The end should read:

Your iteration formula should be

xnew = (2x^3 - 2)/(3x^2 + 2)

so for a start of x=-1

we get

x1 = -1.333333

x2 = -.91919

x3 = -.78357

BTW, x5 = -.770917

which is correct to 7 decimal places.

**Answer this Question**

**Related Questions**

calculus - Use Newton's method to approximate a root of the equation 3sin(x)=x ...

calculus - Use Newton's method to approximate a root of the equation 3sin(x)=x ...

calculus - Use Newton's method to approximate a root of the equation 3sin(x)=x ...

Calculus-Newton Method Approximation - Use Newton's method to approximate the ...

Math - Use Newton's method to approximate a root of the equation 5sin(x)=x as ...

CALC - Use Newton's method to approximate a root of the equation x3+x+3=0 as ...

Cal 1 - Use Newton's method with the specified initial approximation x1 to find ...

calculus, math - Use Newton's method to approximate the value of (543)^(1/5) as ...

Calculus - Use Newton's method with the specified initial approximation x1 to ...

Calculus 1 Newton's Method - Using Newton's method, approximate the root of the ...