(4x^3-9x+8x^2-18)/(x+2)-use synthetic division to divide. I set it up like this (pretend the parentheses are the synthetic division box).
4 8 -27
4 0 -27.
For remainders, according to my book, we're supposed to divide the remainder by the divisor. So it would be -27/-2. Yet my book says there is no remainder. It says the answer is 4x^2-9. How did it get this?
Algebra - Reiny, Tuesday, November 10, 2009 at 10:10pm
Well Jeremiah, it's as simple as your forgetting the -9x term
4 8 -9 -18
I get 4 0 -9 0