1) Two boxes are placed are placed side by side on a frictionless surface so that they touch each other. Box A has a mass of 4 kg. Box B has a mass of 12 kg. A constant force of 24 N is applied to box A. What force does box A exert on box B?

Box A exerts onto force b its acceleration as a force;

So F=ma
where 24=(12+4)a Then solve for a
a=1.5


Then the force that box a exerts on box b is
F=ma
=12*1.5
=18N

Good work.

In order to determine the force box A exerts on box B, we need to understand Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Since box A is applying a force to box B, box B will exert an equal and opposite force on box A.

Therefore, the force that box A exerts on box B is also 24 N.

Hence, the force that box A exerts on box B is 24 N.

To find the force exerted by Box A on Box B, we need to consider Newton's third law of motion, which states that every action has an equal and opposite reaction.

Since Box A experiences a force of 24 N, it will exert an equal and opposite force on Box B. Therefore, Box A exerts a force of 24 N on Box B.