Calculate the amount of heat (in calories) required to raise the temperature of 200g of water from 20C to 50C. The specific heat of water is 1.00 cal/g.
I have done other spacific heat problems but on this one i don't know how to start...
Heat=mass*specific heat*changeinTemp
=200g*1cal/gC*30C
6000 calories?
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amount of heat needed to increase the temperature of 25 grams of water from 25 C TO 50 C
Well, let's dive into this! To calculate the amount of heat required, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat
m is the mass of the substance (in this case, water)
c is the specific heat of the substance (in this case, water)
ΔT is the change in temperature
In your case, the mass of water is 200g and the specific heat of water is 1.00 cal/g. Now, let's find the change in temperature (ΔT):
ΔT = final temperature - initial temperature
= 50C - 20C
= 30C
Now we are ready to substitute the values into the formula:
Q = (200g) * (1.00 cal/g) * (30C)
= 6000 cal
So, the amount of heat required to raise the temperature of 200g of water from 20C to 50C is 6000 calories. That's a hot topic!
To calculate the amount of heat required to raise the temperature of a substance, you can use the formula:
Q = m * c * ∆T
Where:
Q = heat energy (in calories)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in cal/g°C)
∆T = change in temperature (in °C)
In this case, you have:
m = 200g (mass of water)
c = 1.00 cal/g°C (specific heat of water)
∆T = 50°C - 20°C = 30°C (change in temperature)
Now, you can plug these values into the formula to find the amount of heat energy required:
Q = 200g * 1.00 cal/g°C * 30°C
Q = 6000 cal
Therefore, the amount of heat required to raise the temperature of 200g of water from 20°C to 50°C is 6000 calories.