Monday

December 29, 2014

December 29, 2014

Posted by **sh** on Tuesday, November 10, 2009 at 5:43pm.

y=¡î(x©÷+1)

y'=x(x©÷+1)^(-1/2)

y"=[1(x©÷+1)^(-1/2)]-[(1/2)[(x©÷+1)^(-3/2)](2x)(x)]

y"=[(x©÷+1)^(-1/2)]-[(x©÷)(x©÷+1)^(-3/2)]

Is the second derivative right?

- Calculus -
**sh**, Tuesday, November 10, 2009 at 5:54pmy=root(x^2+1)

y'=x(x^2+1)^(-1/2)

y"=[1(x^2+1)^(-1/2)]-[(1/2)[(x^2+1)^(-3/2)](2x)(x)]

y"=[(x^2+1)^(-1/2)]-[(x^2)(x^2+1)^(-3/2)]

- Calculus -
**Reiny**, Tuesday, November 10, 2009 at 7:04pmI agree

**Answer this Question**

**Related Questions**

Applied Calculus - Find the first and second derivative of the function: x/(7x+...

College Calculus 1 - We have to find the first and second derivative of f(x)=x^(...

calculus - Find the first and second derivative - simplify your answer. y=x/4x+1...

calculus - derivatives - can you please find the first 5 derivatives for: f(x...

Derivatives- Math - Can someone explain how to find the derivative of : 1. y= 5...

math - I studied derivatives before, but kind of forgot them all, is there a ...

calculus - Please help with this. I need the first derivative of f(x)=4(x+...

calculus - Differentiate both sides of the double angle identify sin 2x= 2 sin x...

Calculus - I need to find the second derivative of y=x(x-1)^1/2. I found the ...

Calc - 1. Find values of a,b,c, and d such that g(x) = a(x^3)+b(x^2)+cx+d has a ...