A model electric train requires 6 V to operate. If the primary coil of its transformer has 240 windings, how many windings should the secondary have if the primary is connected to a 120 V household circuit?
Vs = 6 V
Vp = 120 V
Np = 240 turns
Ns = ?
Formula: VpNs = VsNp
Solve for Ns:
Ns = Vs/Vp * Np
Ns = 6/120 * 240
Ns = 0.05 * 240
Ns = 12 turns
The voltage ratio equals the turns (a.k.a windings) ratio. More turns, more voltage.
120/6 = 240/N
Solve for N.
120/6 = 240/N
20 = 240/N
(this is where you messed up.
20N=240
N=240/20
N = 240/20
N = 12
To determine the number of windings required for the secondary coil of the transformer, we can use the principle of voltage ratio.
The primary coil is connected to a 120 V household circuit, while the electric train operates on 6 V. Therefore, there is a voltage ratio of 120V/6V = 20 between the primary and secondary coils.
The voltage ratio is directly proportional to the ratio of the number of windings in the primary and secondary coils. So, if the primary coil has 240 windings, we can calculate the number of windings for the secondary coil as follows:
Number of windings in the secondary coil = Number of windings in the primary coil / Voltage ratio
Number of windings in the secondary coil = 240 windings / 20 = 12 windings
Therefore, the secondary coil should have 12 windings.
An electric doorbell uses 12 V to operate. A transformer powered from a 120 V outlet has 500 turns. How many turns are in the secondary
20=240/N
Is the answer 480=N