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September 20, 2014

September 20, 2014

Posted by **Bill** on Tuesday, November 10, 2009 at 4:59am.

The back of the book says it is 8.7 minutes, but I can't figure out how to get that answer.

Thank you for your help.

- Calculus -
**bobpursley**, Tuesday, November 10, 2009 at 6:59amt(0)=200=70+ce^0

solve for c (130)

then

t(3)=70+130e^-k3=180

solve for k

e^-k3=11o/130

-k3=.167

k=.0557

150=70+130e^-(..0557)

-.0557t=.486

t=8.7 min

- Calculus -
**Bill**, Tuesday, November 10, 2009 at 8:31amThank you so much.

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