Posted by Erin on .
I'm not sure how to factor 3x^312x^2+3x. I tried separatring the 3x so that 3x(x+1)(x4, but I got 3x^3+12x^23x^2+12x. Can you show me where I went wrong and how to properly factor this? Is there a general rule or tip for this sort of factoring with a number to the third power? Thanks!!

Algebra 
Reiny,
there is a common factor of 3x
so,
3x^312x^2+3x
= 3x(x^2  4x + 1)
The last part does not factor any more, so that's it.