Posted by **Heather** on Monday, November 9, 2009 at 5:08pm.

Write an equation for the line perpendicular to line XY that contains point Z.

line XY: 3x + 2y = -6, Z(3,2)

I realize that the slope of a perpendicular line is the opposite reciprocal of the first line. But, how do I use point Z in this problem? Thank you.

- Geometry -
**bobpursley**, Monday, November 9, 2009 at 5:13pm
y= -3/2x-3

so the new slope will be 2/3

so then y=2/3 x+b

put point z into the equation, and solve for b.

- Geometry -
**Reiny**, Monday, November 9, 2009 at 5:14pm
Since you know that the slopes of perpendicular lines are opposite reciprocals, you should accept that the new equation must be

2x - 3y = c

plug in the point

6 - 4 = c = 2

so 2x - 3y = 2

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