Geometry
posted by Heather on .
Write an equation for the line perpendicular to line XY that contains point Z.
line XY: 3x + 2y = 6, Z(3,2)
I realize that the slope of a perpendicular line is the opposite reciprocal of the first line. But, how do I use point Z in this problem? Thank you.

y= 3/2x3
so the new slope will be 2/3
so then y=2/3 x+b
put point z into the equation, and solve for b. 
Since you know that the slopes of perpendicular lines are opposite reciprocals, you should accept that the new equation must be
2x  3y = c
plug in the point
6  4 = c = 2
so 2x  3y = 2