Posted by Heather on .
Write an equation for the line perpendicular to line XY that contains point Z.
line XY: 3x + 2y = 6, Z(3,2)
I realize that the slope of a perpendicular line is the opposite reciprocal of the first line. But, how do I use point Z in this problem? Thank you.

Geometry 
bobpursley,
y= 3/2x3
so the new slope will be 2/3
so then y=2/3 x+b
put point z into the equation, and solve for b. 
Geometry 
Reiny,
Since you know that the slopes of perpendicular lines are opposite reciprocals, you should accept that the new equation must be
2x  3y = c
plug in the point
6  4 = c = 2
so 2x  3y = 2