Judy, by chance, spots a potted plant falling outside the window at 3.84 m/s . Further down the same building, Judy boyfriend clocks the pot at 61 m/s .The acceleration of gravity is 9.8 m/s2 .How far apart are the friends?

Answer in units of m.

The time it takes to go between windows is (V2 - V1)/g = 5.833 s

The average velocity during the interval is (V2 + V1)/2 = 32.42 m/s

The product of time and average speed is the distance between them. It must be a tall building!

To find the distance between Judy and her boyfriend, we need to calculate the time it takes for the pot to fall and then use that time to calculate the distance. Here's how we can do it:

1. Start by calculating the time it takes for the pot to fall to the boyfriend's position. We can use the formula:

t = (Vf - Vi) / a

Where:
- Vf is the final velocity of the pot (61 m/s),
- Vi is the initial velocity of the pot (3.84 m/s),
- a is the acceleration due to gravity (9.8 m/s^2).

Substituting the values, we get:
t = (61 m/s - 3.84 m/s) / 9.8 m/s^2

Calculate this value to find the time.

2. Once we have the time, we can calculate the distance between Judy and her boyfriend using the formula:

d = Vi * t

Where:
- Vi is the initial velocity of the pot (3.84 m/s),
- t is the time calculated in step 1.

Substitute the values and calculate to find the distance.

Following these steps, we can find the distance between the two friends.