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October 20, 2014

October 20, 2014

Posted by **Anonymous** on Sunday, November 8, 2009 at 5:25pm.

- physics -
**bobpursley**, Sunday, November 8, 2009 at 6:26pmbreak up the initial velocity into vertical and horizontal components.

distancehorizontal=vix*t=16cos66*t

you know distance (33m),solve for time.

Vvf=Viv+gt Viv= 16sin66, and you know time.

vf=sqrt(vvf^2+vix^2)

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