Posted by **Anonymous** on Sunday, November 8, 2009 at 5:25pm.

A ball is thrown from the top of a building upward at an angle of 66 ◦ to the horizontal and with an initial speed of 16 m/s. The ball is thrown at a height of 53 m above the ground and hits the ground 33.2074 m from the base of the building. The acceleration of gravity is 9.8 m/s2 . What is the speed of the ball just before it strikes the ground? Answer in units of m/s.

- physics -
**bobpursley**, Sunday, November 8, 2009 at 6:26pm
break up the initial velocity into vertical and horizontal components.

distancehorizontal=vix*t=16cos66*t

you know distance (33m),solve for time.

Vvf=Viv+gt Viv= 16sin66, and you know time.

vf=sqrt(vvf^2+vix^2)

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