Sunday
November 23, 2014

Homework Help: Calc

Posted by Joe on Sunday, November 8, 2009 at 5:12pm.

A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a culture is 59 cells. (The tolerance is 1% unless your instructor states otherwise.)

(a) Find the relative growth rate.

(b) Find an expression for the number of cells after t hours.

(c) Find the number of cells after 5 hours.

(d) Find the rate of growth after 5 hours.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

calculus - A common inhabitant of human intestines is the bacterium Escherichia ...
Calculus - The growth rate of Escherichia coli, a common bacterium found in the ...
Math - The growth rate of Escherichia coli, a common bacterium found in the ...
Math - The growth rate of Escherichia coli, a common bacterium found in the ...
Physics - The bacterium Escherichia coli (or E. coli) is a single-celled ...
Chemistry - The Heisenberg Uncertainty Principle: A student is examining a ...
Chemistry - The Heisenberg Uncertainty Principle: A student is examining a ...
Urgent Chemistry - The Heisenberg Uncertainty Principle: A student is examining ...
7th grade science - problem:suppose a bacterium reproduces by binary fission ...
math 12 - The bacterium Escherichia coli, or E-coli, has a doubling period of 0....

Search
Members