posted by Angel on .
When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 5.0 M HCI is required to react completely with 3.00 g of magnesium?
The Chemical reaction is:
Mg + 2HCl --> MgCl2 + H2
1) Divide the grams of Mg by the atomic mass of Mg to get moles of Mg.
2) Moles of HCl = (2)(moles of Mg)
3) Moles of HCl = (V)(5.0 mol/L)
Volume of HCl = (mol. HCl) / (5.0 mol/L)
NOTE: The volume of HCl will be in liters
If 5.00 g of manganese (IV) oxide reacts with 25.0 mL of 6.00 M hydrochloric acid, what is the calculated mass of chlorine gas produced?