Posted by Anonymous on Sunday, November 8, 2009 at 8:45am.
First find the mean. Then find the difference of each score from the mean. (As a check, the sum of these differences should be zero.) Square each difference and find their sum. Divide that sum by n (number of scores) to get your variance.
I'll let you do the work.
I hope this helps. Thanks for asking.
I wouldn't want you to do the work, so thank you!
Mean is 6.8
6.8-8.5=-1.7^2=2.89
6.8-4.5=2.3^2=5.29
6.8-8.8=-2^2=4
6.8-6.9=-0.1^2=0.1
6.8-5.3=1.5^2=2.25
14.53/5=2.906
1.705
Is my work correct? I think I messed up somewhere in the process.
And I wanted to ask is it standard for the sums to always add up to 0? Thank you for that tip.
Doesn't .1 * .1 =.01?
However, I did not check the whole process.
The sum of the differences from the mean will always add to zero, assuming that you have not made a mistake.
Remember that the mean acts as a balance point for the distribution, so the scores on one side (+) must equal the scores on the other (-).
Mean is 6.8
6.8-8.5=-1.7^2=2.89
6.8-4.5=2.3^2=5.29
6.8-8.8=-2^2=4
6.8-6.9=-0.1^2=0.01
6.8-5.3=1.5^2=2.25
14.44/5=2.888 So the variance is 2.9!!
1.6994
Wow! Thanks for catching that, it changed the entire process. I appreciate your help.
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