A violin string has a standard length of 32.8 cm. It sounds the musical note A (440Hz) when played without fingering.

How far from the end of the string should you place your finger to play the note C (523Hz)? answer should be in cm.

You want the vibrating part of the stng to be 440/523 of the original length, to decrease the wavelngth by that factor. (The frequency will be higher by the inverse factor 523/440.)

440/523 x 32.8 = 27.6 cm. The finger should be moved 32.8 - 27.6 = 5.2 cm from the end of the string.

you saved my life....thanks

Well, let me put on my thinking cap! Or should I say, my funny hat? Anyway, to find the answer, we need to use a little math and a whole lot of musical magic!

Let's start with some funny math, shall we? If the frequency of the A note is 440Hz and the frequency of the C note is 523Hz, we can calculate the ratio between their frequencies. So, hold onto your funny bone, because here comes some wacky math!

523Hz / 440Hz = 1.188

Now, if we take the square root of that ratio (don't ask me why, I didn't write the rules), we get:

√1.188 ≈ 1.090

So, what does this have to do with your question? Well, that magic number, 1.090, is the ratio of the length of the string that you need to play to get the C note. In other words, if you want to play C, you need to place your finger at 1.090 times the distance from the end of the string.

Now, if we multiply this ratio by the standard length of the string (32.8cm), we get:

1.090 * 32.8cm ≈ 35.77cm

So, to play the C note, you should place your finger approximately 35.77cm from the end of the violin string.

But remember, this answer is brought to you by the world of humor, so take it with a pinch of clownish charm!

To calculate the distance from the end of the string to play the note C (523Hz), we can use the formula for the relationship between frequency and length of a string:

Frequency1 / Frequency2 = Length1 / Length2

Let's substitute the given values:

440Hz / 523Hz = 32.8cm / x

To find x, we can cross multiply and solve for x:

440Hz * x = 523Hz * 32.8cm
x = (523Hz * 32.8cm) / 440Hz

Now, let's calculate the value of x:

x = (523 * 32.8) / 440
x ≈ 38.99 cm

Therefore, to play the note C (523Hz) on the violin string, you should place your finger approximately 38.99 cm from the end of the string.

To determine the distance from the end of the violin string to place your finger in order to play the note C (523Hz), we can use the concept of the harmonic series.

The fundamental frequency (f1) of a vibrating string is inversely proportional to its length (L), which means that:

f1 ∝ 1/L

Given that the string has a standard length of 32.8 cm and sounds the note A (440Hz), we can calculate its fundamental frequency (f1):

f1 = 440Hz

Using the relationship mentioned above:

f1 = 1/L

We can rearrange the equation to solve for L:

L = 1/f1

Substituting the value for f1, we find:

L = 1/440Hz

L ≈ 0.00227 cm (rounded to five decimal places)

Now, to find the position where you should place your finger to play the note C (523Hz), we can use the fact that the frequency of a note is directly proportional to the length of the vibrating string.

Let x represent the distance between the finger position and the end of the string (in cm). The frequency of the note C (523Hz) can be related to the length of the vibrating portion of the string (L - x) as follows:

f2/f1 = (L - x)/L

Substituting the known values into the equation:

523Hz/440Hz = (32.8cm - x)/32.8cm

Using cross-multiplication, we can solve for x:

x = (523Hz * 32.8cm) / 440Hz

x ≈ 39.15cm (rounded to two decimal places)

Therefore, to play the note C (523Hz) on the violin string with a standard length of 32.8cm, you should place your finger approximately 39.15cm from the end of the string.