Posted by N. on Saturday, November 7, 2009 at 8:26pm.
The Doppler shift, delta f, of the blood cells moving away is 2 V/v_sound * 5.0 *10^6 Hz.
V = 0.15 m/s = the blood cell speed and v_sound = 1540 m/s.
The factor of 2 is there because the frequency is shifted twice (when received and when sent back).
delta f = 2*5*10^6*0.15/1540 = 974 Hz
The beat frequency (of the transmitted beam combined with the reflected beam)equals delta f
thank you Drwls
thank you
perfect answer...thank you so much
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