Posted by **Joe** on Saturday, November 7, 2009 at 7:02pm.

A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16kg mixture was worth $6.70/kg. How many kilograms of each type was used?

- algebra -
**Reiny**, Saturday, November 7, 2009 at 7:08pm
Let the amount of the $6 mixture used be x kg

let the amount of the $8.80 mixture be 16-x kg

then

6x + 8.8(16-x) = 6.7(16)

solve for x

- algebra -
**mo**, Saturday, May 11, 2013 at 7:46pm
thnx SO MUCH

- algebra -
**Robby**, Monday, February 10, 2014 at 5:30pm
6x+1408-88x=1072

you may move the decimal 1 place if you want

1408-82x=1072

1408-1072=82x

336=88x

x=336/88

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