algebra
posted by Joe on .
A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16kg mixture was worth $6.70/kg. How many kilograms of each type was used?

Let the amount of the $6 mixture used be x kg
let the amount of the $8.80 mixture be 16x kg
then
6x + 8.8(16x) = 6.7(16)
solve for x 
thnx SO MUCH

6x+140888x=1072
you may move the decimal 1 place if you want
140882x=1072
14081072=82x
336=88x
x=336/88