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Posted by on Saturday, November 7, 2009 at 7:02pm.

A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16kg mixture was worth $6.70/kg. How many kilograms of each type was used?

  • algebra - , Saturday, November 7, 2009 at 7:08pm

    Let the amount of the $6 mixture used be x kg
    let the amount of the $8.80 mixture be 16-x kg

    then
    6x + 8.8(16-x) = 6.7(16)

    solve for x

  • algebra - , Saturday, May 11, 2013 at 7:46pm

    thnx SO MUCH

  • algebra - , Monday, February 10, 2014 at 5:30pm

    6x+1408-88x=1072
    you may move the decimal 1 place if you want
    1408-82x=1072
    1408-1072=82x
    336=88x
    x=336/88

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