Homework Help Forum: Calculus

Posted by Z32 on Friday, November 6, 2009 at 4:30pm.

f(x) = [3/x^2] - [5/x^7], F(x) is the antiderivative of f(x) with F(1)=0. F(x) = ? I have no idea how to approach this problem. The fractions are scaring me.

• Calculus - bobpursley, Friday, November 6, 2009 at 4:37pm

  This is really pretty simple, I can't imagine how you are stuck. INTf(x)= INT 3x^-2 dx -INT (5x^-7)dx = -3x^-1 +5/6 x^-6 +C F(1)=0 = -3+5/6+C=1 solve for C. F(x) = -3x^-1 +5/6 x^-6 check my work, it is easy to make a typo

  
  

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