Post a New Question

math

posted by on .

A salesperson bought a caase of pens.On Monday, he sold 1/2 of the pens.On Tuesady, he sold 30 more.On Wednesday, he sold 1/3 of the pens that were left.On Thursday, he sold the remaining 40 pens.How many pens were originally in the case,

  • math - ,

    96

  • math - ,

    96 is a nice number, but it is not the answer to your problem.

    Let x = total number of pens

    .5x = Monday sales, which means that .5x remain.
    30 = Tuesday sales
    1/3(.5x-30) = Wednesday sales
    40 remained on Thursday

    .5x - 30 - 1/3 (.5x -30) = 40

    Solve for x.

    I hope this helps. Thanks for asking.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question