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December 22, 2014

December 22, 2014

Posted by **for "bobpursley"** on Friday, November 6, 2009 at 2:53pm.

So, I used

mg(h+x)=1/2 k x^2

then solved for x in each case.

and got 2 different values out of the quadratic formula:

-0.223 m and -0.0000242 m

given the question, how can I rule one of the answers out and choose the reasonable answer?

- Physics -
**bobpursley**, Friday, November 6, 2009 at 3:02pm6000x^2-40kx- 40*9.8*1=0 where k is 1, or 10

x= (+40k+-sqrt(1600k^2+9.4E6)/12,000

for k=1

x= (40+-3067)/12000= 25cm ignore the -x, it has no physical meaning, the trampoline will not deform upward.

for k=10

x= (+400+-sqrt(160000+9.4E6)/12000

x=(400+-3093)/12000=29cm

check my math.

- Physics -
**Rachel**, Friday, November 6, 2009 at 3:06pmyou lost be. k= 12 000 N/m

where are you getting 1 or 10

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