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October 30, 2014

October 30, 2014

Posted by **scooby** on Friday, November 6, 2009 at 1:27pm.

- math algebra -
**bobpursley**, Friday, November 6, 2009 at 1:32pmThey are 1/2 hour apart. To catch up, they have to travel the same distance.

d=100(t)

d=110(t-.5)

set them equal

100t=110t-55

55=10t

t= 5.5 hrs.

check my thinking.

- math algebra -
**scooby**, Friday, November 6, 2009 at 1:54pmwould that be 11:30 am?

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