Homework Help Forum: Physics

Posted by natalia on Friday, November 6, 2009 at 9:48am.

A rollercoaster car starts at rest on top of a frictionless hill of height 17 m, slides down to ground level, and then into a frictionless loop of radius 5 m. When the car is at the side of the loop (level with the center), find the magnitude of the car's tangential acceleration:

• Physics - bobpursley, Friday, November 6, 2009 at 9:53am

  It fell a distance of 12 m, so it has that energy as velocity. mg(h)=1/2 mv^2 mg dh/dt= m dv/dt g dh/dt= dv/dt now dv/dt is tangential acceleration. dh/dt is tangential velocity. You can get velocity from 1/2 mv^2=mgh for h=12

  
  

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