Post a New Question

Physics

posted by on .

A rollercoaster car starts at rest on top of a frictionless hill of height 17 m, slides down to ground level, and then into a frictionless loop of radius 5 m.

When the car is at the side of the loop (level with the center), find the magnitude of the car's tangential acceleration:

  • Physics - ,

    It fell a distance of 12 m, so it has that energy as velocity.

    mg(h)=1/2 mv^2
    mg dh/dt= m dv/dt

    g dh/dt= dv/dt

    now dv/dt is tangential acceleration.
    dh/dt is tangential velocity. You can get velocity from
    1/2 mv^2=mgh for h=12

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question