Friday

February 27, 2015

February 27, 2015

Posted by **natalia** on Friday, November 6, 2009 at 9:48am.

When the car is at the side of the loop (level with the center), find the magnitude of the car's tangential acceleration:

- Physics -
**bobpursley**, Friday, November 6, 2009 at 9:53amIt fell a distance of 12 m, so it has that energy as velocity.

mg(h)=1/2 mv^2

mg dh/dt= m dv/dt

g dh/dt= dv/dt

now dv/dt is tangential acceleration.

dh/dt is tangential velocity. You can get velocity from

1/2 mv^2=mgh for h=12

**Answer this Question**

**Related Questions**

colledge physics - A block of mass 0.78kg starts from rest at point A and slides...

Physics Help.. - A small cube (m=0.290 kg) is at a height of 261 cm up a ...

physics - A block of mass 0.78kg starts from rest at point A and slides down a ...

physics - A mass m = 88.0 kg slides on a frictionless track that has a drop, ...

physics - A 500kg roller coaster starts from rest at points 35m above the ground...

physics - A mass m = 76.0 kg slides on a frictionless track that has a drop, ...

physics - A mass m = 76.0 kg slides on a frictionless track that has a drop, ...

PHYSICS - An 800.0 kg roller coaster car is at rest at the top of a 95 m hill. ...

physics - 4. An 800.0 kg roller coaster car is at rest at the top of a 95 m hill...

physics - A mass m = 73 kg slides on a frictionless track that has a drop, ...