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July 22, 2014

July 22, 2014

Posted by **natalia** on Friday, November 6, 2009 at 9:48am.

When the car is at the side of the loop (level with the center), find the magnitude of the car's tangential acceleration:

- Physics -
**bobpursley**, Friday, November 6, 2009 at 9:53amIt fell a distance of 12 m, so it has that energy as velocity.

mg(h)=1/2 mv^2

mg dh/dt= m dv/dt

g dh/dt= dv/dt

now dv/dt is tangential acceleration.

dh/dt is tangential velocity. You can get velocity from

1/2 mv^2=mgh for h=12

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