A rancher wants to fence in an area of 500000 square feet in a rectangular field and then divide it in half with a fence down the middle, parallel to one side.
What is the shortest length of fence that the rancher can use?
Calculus - Reiny, Friday, November 6, 2009 at 8:41am
I will set it up for you.
Let the length of the rectangle be y feet
let its width be x feet. The divider will then be x feet
So the length L
= 3x + 2y
but you know that xy = 500000
and y = 500000/x
L = 3x + 2(500000/x)
differentiate, set that equal to zero and solve for x
Put x back into L = ...
and you are done
Calculus - lkl, Thursday, November 29, 2012 at 12:01pm