Homework Help Forum: physics

Posted by ami on Friday, November 6, 2009 at 3:37am.

At what displacement from the equilibrium is the total energy of a simple harmonic oscillator one - sixths KE and five - sixth PE? Answer should be in terms of the amplitude A.

• physics - drwls, Friday, November 6, 2009 at 5:11am

  Let A be the full amplitude displacement and k be the sping constant. The maximum total energy is Et = (1/2) k A^2 The potential energy for other displacements is Ep = (1/2) k x^2 Ep/Et = 5/6 when (x/A)^2 = 5/6 x/A = 0.91287

  
  

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