Posted by Anonymous on Thursday, November 5, 2009 at 11:10pm.
Find the common ratio and write out the first four terms of the geometric sequence bracket (3 to the power of n1)/(10) bracket
???? please help me!

math  drwls, Thursday, November 5, 2009 at 11:21pm
For n=1, 3^(n1)/10 = 1/10
For n=2, 3^1/10 = 3/10
For n=3, 3^2/10 = 9/10
For n=4, 3^3/10 = 27/10
The ratio of successive terms is 3.
I don't know why you wrote "bracket" at the end of your question.

math  Anonymous, Thursday, November 5, 2009 at 11:37pm
there are two brackets, one on each side of the problem. The ratio was right thank you! But it said the n=14 was wrong?

math  Anonymous, Sunday, September 11, 2011 at 4:45pm
what is the answer for 15460 divide by ten?
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