Homework Help Forum: Math

Posted by Shelby on Thursday, November 5, 2009 at 10:47pm.

Find the 6th term of the geometric sequence with a4=256/625 and a11=-4194304/48828125

• Math - Reiny, Thursday, November 5, 2009 at 10:58pm

  term 4 = ar^3 = 256/625 term 11 = ar^10 = -4194304/48828125 so dividing the second by the first: r^7 = 16384/78125 r = 4/5 so 256/625 = a(4/5)^3 a = 4/5 so term 6 = ar^5 = (4/5)(4/5)^5 = (4/5)^6 = 4096/15625

  
  

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