Homework Help Forum: Honors Chemistry

Posted by Emily on Thursday, November 5, 2009 at 9:05pm.

Can someone check my first answer and help me with the second question? Thanks so much!! :D 1. N2 + 3H2 ==> 2NH3 : How many grams of NH3 can be produced from the reaction of 28 g of N2 and 25 g of H2? ==> I got 37.5 grams. 2. How much of the excess reagent in Problem 1 is left over? ==> I really have no idea how to do this. Can someone please explain this to me? Thanks!

• Honors Chemistry - MathMate, Thursday, November 5, 2009 at 9:42pm

  1. N2 + 3H2 ==> 2NH3 (balanced equation) Now put the RAM (relative atomic masses) to each reactant. 2*14 + 3*2 ==> 2*(17) 28 + 6 ==> 34 Therefore 28 grams of N2 with 6 grams of H2 will yield 34 grams of NH3 (assuming one of the reactants will be exhausted). 2. Since only 6 grams of H2 out of 25 grams has been used for the reaction, what would be the quantity left?

  
  

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