Posted by SC on Thursday, November 5, 2009 at 8:17pm.
I agree with your first part: b=2^(1/4) = 1.189207.
Now, after 3 days, according to the question, we must have 84.089 spiders - wonder what .089 of a spider looks like? - and after 8 days, we have 100.
If S0 is the number of spiders on day zero, and s is the multiplication rate of spiders, then
S0 * s^3 = 84.089
S0 * s^8 = 100
From which we can quickly get s^5.
And then we get s.
And from there, there's not much left to do, I think.
I made a mistake. after eight days , its 199.99 spiders.
I still don't understand how would we get s?
You didn't make a mistake:
"Eight days after moving in, there were four times as many termites as spiders"
But 100 * (2^.25)^8 = 400 (termites)
So if there were 400 termites, there were 100 spiders.
So how do we get s?
S0 * s^3 = 84.089
S0 * s^8 = 100
(S0 * s^8) / (S0 * s^3)
= s^5
= 100 / 84.089
s = (100 / 84.089)^(1/5)
Ohh all i needed to do was divide! heh thanks a lot!
You're welcome!
you guys never gave an answer..
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