Physics
posted by Letisha on .
In the parallel spring system, the springs
are positioned so that the 44 N weight
stretches each spring equally. The spring con
stant for the lefthand spring is 3.6 N/cm and
the spring constant for the righhand spring
is 6.4 N/cm.
How far down will the 44 N weight stretch
the springs?
Answer in units of cm.

The forces are additive.
F1+F2=44N
3.6*x+6.4x=44
solve for x.