Saturday

November 29, 2014

November 29, 2014

Posted by **Letisha** on Thursday, November 5, 2009 at 7:39pm.

are positioned so that the 44 N weight

stretches each spring equally. The spring con-

stant for the left-hand spring is 3.6 N/cm and

the spring constant for the righ-hand spring

is 6.4 N/cm.

How far down will the 44 N weight stretch

the springs?

Answer in units of cm.

- Physics -
**bobpursley**, Thursday, November 5, 2009 at 7:41pmThe forces are additive.

F1+F2=44N

3.6*x+6.4x=44

solve for x.

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