Posted by Anmol on Thursday, November 5, 2009 at 5:37pm.
Also this is assumed that it occurs at 1 atm. and the final temperature of the water is the same temperature of the gas.
You start by writing the equation and balancing it.
2K + 2H2O ==> 2KOH + H2
Then you pray over it. I think you must have either delta H or the final T. Check my thinking.
no neither of them are given..just the assumptions i mentioned
Use the equation above for the balanced equation. Convert 5.00 g K metal to moles. moles = grams/molar mass.
Then use the coefficients in the balanced equation to convert moles K metal to moles KOH and in a separate calculation determine the moles H2 gas.
(KOH) = moles/kg solvent = molality.
Volume of H2 gas at STP = (22.4 L/mol) x moles H2 from above. Then convert from STP to 24 degrees celsius.
Finally, you can't calculate delta H without the final T and you can't calculate final T without delta H.
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