Posted by Anonymous on Thursday, November 5, 2009 at 5:35pm.
I will be happy to critique your thinking.
Projectile motion equation:
y=xtan(è)-(gx^2)/[2(ucos(è))^2] where
è=39.5 deg., u -34.9 met/sec & g=9.8 met/sec^2. On substitution and solving for y=0, you can get the horizontal range as 122.003 met. and thus the time required would be = 122.003/(ucos(è))=4.53043 sec.
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