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October 2, 2014

October 2, 2014

Posted by **jenny** on Thursday, November 5, 2009 at 5:08pm.

- calculas -
**MathMate**, Thursday, November 5, 2009 at 5:50pmA critical point in the domain of x is a value of x at which the function is not differentiable or where the derivative is zero.

See: http://en.wikipedia.org/wiki/Critical_point_%28mathematics%29

For the case in point:

f(x)= (8x-7)e^2x

f'(x) can be found using the product rule and the chain rule as

f'(x):=2(8x-3)*e^(2x)

Setting f'(x)=0 and solving for x, we get e^2x=0 or x=3/8.

Since the range of e^2x excludes 0, it is a solution to be rejected. So the unique point required is x=3/8.

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