Hello,

((((((I need the answer in a hour from my posting)))))
I have been posting this problme for four days ago, so please show Sympathy.
I solved it but I want to be 100% su ...there is moreshow problem
Hello,

((((((I need the answer in a hour from my posting)))))
I have been posting this problme for four days ago, so please show Sympathy.
I solved it but I want to be 100% sure to go on.

The result of Silicon crystal analyzation shown that there is an amount of arsenic As atoms in silicon crystal at Concentrate percentage which is 0.0002%. assuming if conductivity concentration which promote by heat is an eliminated amount.
Find out the electrical conducting density?

Where Molarity of silicon = 12.1cm3/mole
my humble ideas goes like,
Density= w/v....1
V= Moles#/Molarity....2

1/Calculation of moles number:

Moles#=w/M.wt....3
= .0002*100/28.1
=7.117*10^-4 mole

2/ Calculation of volume:
back to equation #2
V=7.117*10^-4/12.1
=5.88*10-5 cm3

If I do it in appropriate way why I couldn't find the Weight in grams of Si. Hold on, silicon is the conductive and arsenic is a blotch which give us a N-type conducting. Avoiding the weight of Si we can go throw this rule which says: Density =the number of conductive * 1 cm3
Where 1 cm3 = 1mole =Avogadro’s number
1 mole = 6.022 x 10^23 atoms
Now, how could I figure out the number of conductive?
How can I solve this, Am I doing well ?!

Draw the diagram of band and name the form of boundary

Finding out the Si weight
W of Si =moles#/atomic mass
= 7.117*10^-4/28.086
= 2.534*10^-5gm
Back to density
D = 2.534*10^-5/5.88*10^-5
= 0.4309gm/cm3
Another solution
segma= 1/D
Log segma = 4.247 –(92924/T)
=2.7221998*10^-6 ms
D = 367.349*10^3

I really need help.
Electrical conductivity or specific conductance

is a measure of a material's ability to conduct an electric current. When an electrical potential difference is placed across a conductor, its movable charges flow, giving rise to an electric current. The conductivity s is defined as the ratio of the current density J to the electric field strength E

J=sE

where electrical conductivity s is has been calculated
means it can be found in table as a constant.

!!!!!!!!!
Any Ideas!

will I have an answer any time soon?!
please respond

Your question(s) and answer(s)(?) are so disorganized that I can't make heads or tails of the question(s), much less how you propose to solve it(them).

Thanks dr Bob for your reply.

Here's the organized version
Question:
Result of Silicon crystal analyzation shown that there is an amount of arsenic As atoms in silicon crystal at Concentrate percentage which is 0.0002%. Assuming if conductivity concentration which promote by heat is an eliminated amount.
Find out the electrical conducting density?
Where Molarity of silicon = 12.1cm3/mole.
Answer:
We get N-type semiconductor
Density= w/v....(1)
V= Moles#/Molarity....(2)

1/Calculation of moles number:
Moles#=w/M.wt....(3)
= .0002*100/28.1
=7.117*10^-4 mole

2/ Calculation of volume:
back to equation #2
V=7.117*10^-4/12.1
=5.88*10-5 cm3

3/W of Si =moles#/atomic mass
= 7.117*10^-4/28.086
= 2.534*10^-5gm

Back to density
D = 2.534*10^-5/5.88*10^-5
= 0.4309 gm/cm3
Question: where could the previous answer take me to?
Question:
Dose electrical conductivity density try to tell me something about which of charge transfers (holes or electrons) have majority on other?
Information:
I'm already know that it's N-type SC which means the charge transfer is electron.
Question:
Did I need to find the electron numbers?

To find the electrical conductivity of the silicon crystal, you have already calculated the density of the silicon crystal. Now, you need to find the number of conductive atoms in the crystal.

You can find the number of conductive atoms by considering that 1 cm^3 of silicon crystal contains 1 mole of atoms. Since 1 mole of any substance contains 6.022 x 10^23 atoms (Avogadro's number), the number of conductive atoms in 5.88 x 10^-5 cm^3 of the silicon crystal can be calculated as:

Number of conductive atoms = (Number of moles of silicon) * (Number of atoms in 1 mole)
= (7.117 x 10^-4 mole) * (6.022 x 10^23 atoms/mole)
= 4.288 x 10^20 atoms

Now, you can calculate the electrical conductivity using the formula J = sE, where J is the current density, s is the electrical conductivity, and E is the electric field strength.

Since the problem statement doesn't provide the values for J and E, it seems that they are not needed for this calculation. Instead, it mentions that the electrical conductivity (s) can be found in a table as a constant.

Therefore, you would need to consult a reference source or table that provides the electrical conductivity of silicon with a specific doping concentration of arsenic. This information can vary depending on the exact conditions and parameters of the crystal.